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प्रश्न
Rationalize the denominator.
`1/(sqrt 3 - sqrt 2)`
उत्तर
`1/(sqrt 3 - sqrt 2)`
`= 1/(sqrt 3 - sqrt 2) xx ((sqrt3+ sqrt 2))/((sqrt3+ sqrt2))`
`= ((sqrt 3 + sqrt 2))/((sqrt 3)^2 - (sqrt 2)^2) ...[(a+b)(a-b) = a^2 - b^2]`
`= ((sqrt 3 + sqrt 2))/(3 - 2)`
`= sqrt 3 + sqrt 2`
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संबंधित प्रश्न
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