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प्रश्न
The p.d.f. of r.v. of X is given by
f (x) = `k /sqrtx` , for 0 < x < 4 and = 0, otherwise. Determine k .
Determine c.d.f. of X and hence P (X ≤ 2) and P(X ≤ 1).
उत्तर
Since, f is p.d.f. of the r.v. X,
` int_(-∞)^∞ f(x) dx = 1`
∴ `int_(-∞)^∞ f(x) dx + int_(-0)^4 f(x) dx + int_(4)^∞ f(x) dx = 1`
∴`0 + int_(0)^4 k /sqrtx dx + 0 = 1`
∴ `k int_(0)^4 x ^(-1/2) dx = 1`
∴ `k[x^(1/2)/(1/2)]_0^4 =1`
∴ 2k[2 - 0] = 1
∴ 4k = 1
∴ k = `1/4`
Let F(X) be the c.d.f. of X.
∴ F(X) = P(X ≤ x) = `int_(-∞)^x f(x) dx`
= `int_(-∞)^0 f (x) dx + int_(0)^x f(x) dx`
= `0 + int_(0)^x k /sqrtx dx`
= `k int_(0)^x x ^(-1/2) dx`
= `k[x^(1/2)/(1/2)]_0^x`
= `2k sqrtx = 2(1/4) sqrtx` .....[∵ k = `1/4`]
∴ F(X) = `sqrtx /2`
P(X ≤ 2) = F (2) = `sqrt2/2 = 1/sqrt2`
P(X ≤ 1) = F (1) = `sqrt1/2 = 1/2`
Hence, `k 1/ 4 ,P (X ≤ 2) = 1/sqrt2 , P (X ≤ 1) = 1/2`
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