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प्रश्न
The period of oscillation of a body of mass m1 suspended from a light spring is T. When a body of mass m2 is tied to the first body and the system is made to oscillate, the period is 2T. Compare the masses m1 and m2
उत्तर
T = `2πsqrt("m"/"k")`
∴ `(2"T")/"T"` = 2 = `sqrt(("m"_1+"m"_2)/"m"_1)`
∴ `("m"_1+"m"_2)/"m"_1` = 4
∴ `"m"_2/"m"_1=3/1`
∴ `"m"_1/"m"_2=1/3`
This gives the required ratio of the masses.
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