मराठी

Using integration, find the area of the region bounded between the line x = 4 and the parabola y2 = 16x. - Mathematics

Advertisements
Advertisements

प्रश्न

Using integration, find the area of the region bounded between the line x = 4 and the parabola y2 = 16x.

बेरीज

उत्तर

The shaded region OACO is the region bounded by the parabola y2 = 16x and the line x = 4.

The area OACO is symmetrical about X-axis.

Area of OACO = 2(Area of OAB)

= `2 int_0^4 "y dx"`

= `2 int_0^4 4sqrt"x"  "dx"`

= `8 xx 2/3 ["x"^(3//2)]_0^4`

= `16/3 (4)^(3//2)`

= `16/3 xx 8`

= `128/3`

So, the required area is `128/3` sq. units.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2021-2022 (April) Set 1

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the area bounded by the curve y2 = 4axx-axis and the lines x = 0 and x = a.


Using integration, find the area bounded by the curve x2 = 4y and the line x = 4y − 2.


Find the area of the region bounded by the curve x2 = 16y, lines y = 2, y = 6 and Y-axis lying in the first quadrant.


Using the method of integration find the area of the region bounded by lines: 2x + y = 4, 3x – 2y = 6 and x – 3+ 5 = 0


Using integration, find the area of the region bounded by the line y − 1 = x, the x − axis and the ordinates x= −2 and x = 3.


Draw a rough sketch of the graph of the curve \[\frac{x^2}{4} + \frac{y^2}{9} = 1\]  and evaluate the area of the region under the curve and above the x-axis.


Sketch the graph y = | x − 5 |. Evaluate \[\int\limits_0^1 \left| x - 5 \right| dx\]. What does this value of the integral represent on the graph.


Show that the areas under the curves y = sin x and y = sin 2x between x = 0 and x =\[\frac{\pi}{3}\]  are in the ratio 2 : 3.


Find the area of the region bounded by the curve \[a y^2 = x^3\], the y-axis and the lines y = a and y = 2a.


Find the area of the region \[\left\{ \left( x, y \right): \frac{x^2}{a^2} + \frac{y^2}{b^2} \leq 1 \leq \frac{x}{a} + \frac{y}{b} \right\}\]


Using integration, find the area of the region bounded by the triangle whose vertices are (2, 1), (3, 4) and (5, 2).


Using the method of integration, find the area of the region bounded by the following lines:
3x − y − 3 = 0, 2x + y − 12 = 0, x − 2y − 1 = 0.


Using integration, find the area of the triangle ABC coordinates of whose vertices are A (4, 1), B (6, 6) and C (8, 4).


If the area bounded by the parabola \[y^2 = 4ax\] and the line y = mx is \[\frac{a^2}{12}\] sq. units, then using integration, find the value of m. 

 


Find the area bounded by the parabola x = 8 + 2y − y2; the y-axis and the lines y = −1 and y = 3.


Find the area of the region bounded by the parabola y2 = 2x and the straight line x − y = 4.


The area bounded by the parabola y2 = 4ax and x2 = 4ay is ___________ .


The area bounded by the curve y = x |x| and the ordinates x = −1 and x = 1 is given by


Area lying in first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2, is


The area of the region bounded by the curve y = x2 + x, x-axis and the line x = 2 and x = 5 is equal to ______.


Find the area of region bounded by the triangle whose vertices are (–1, 1), (0, 5) and (3, 2), using integration.


The area of the region bounded by the y-axis, y = cosx and y = sinx, 0 ≤ x ≤ `pi/2` is ______.


The area of the region bounded by the circle x2 + y2 = 1 is ______.


The area of the region bounded by the line y = 4 and the curve y = x2 is ______. 


Area of the region bounded by the curve y = |x + 1| + 1, x = –3, x = 3 and y = 0 is


Find the area of the region bounded by the curve `y^2 - x` and the line `x` = 1, `x` = 4 and the `x`-axis.


Find the area of the region bounded by the ellipse `x^2/4 + y^2/9` = 1.


Smaller area bounded by the circle `x^2 + y^2 = 4` and the line `x + y = 2` is.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×