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Question
\[\frac{1 - \tan^2 45°}{1 + \tan^2 45°}\] is equal to
Options
tan 90°
1
sin 45°
sin 0°
Solution
We have to find the value of the following
`(1- tan^2 45°)/(1+tan^2 45°)`
so
`(1-tan^2 45°)/(1+tan^2 45°)`
=`(1-(-1)^2)/(1+(1)^2)`
=`0/1`
=` 0`
We know that tan `45°=1`
` sin 0°=0`
= `sin 0°`
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