Advertisements
Advertisements
Question
A quadrilateral PQRS is drawn to circumscribe a circle. If PQ = 12 cm, QR = 15 cm and RS = 14 cm, then find the length of SP is ______.
Options
15 cm
14 cm
12 cm
11 cm
Solution
A quadrilateral PQRS is drawn to circumscribe a circle. If PQ = 12 cm, QR = 15 cm and RS = 14 cm, then find the length of SP is 11 cm.
Explanation:
A quadrilateral PQRS is drawn to circumscribe a circle.
Hence,
PQ + RS = QR + SP
12 + 14 = 15 + SP
SP = 26 – 15
SP = 11 cm
APPEARS IN
RELATED QUESTIONS
In the below given figure, two tangents RQ and RP are drawn from an external point R to the circle with centre O. If∠PRQ = 120°, then prove that OR = PR + RQ.
Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.
Prove that a parallelogram circumscribing a circle is a rhombus.
In the figure, AB and CD are common tangents to two circles of unequal radii. Prove that AB = CD.
Find the area of the shaded region in Fig. 8, where \\
In Fig. 4, a circle is inscribed in a ΔABC having sides BC = 8 cm, AB = 10 cm and AC = 12 cm. Find the lengths BL, CM and AN.
The length of tangent from an external point P on a circle with centre O is always less than OP.
From a point P, two tangents PA and PB are drawn to a circle C(0, r). If OP = 2r, then find ∠APB. What type of triangle is APB?
Draw two concentric circles of radii 2 cm and 3 cm. From a point on the outer circle, construct a pair of tangents to the inner circle.
In the given figure, PA and PB are tangents from external point P to a circle with centre C and Q is any point on the circle. Then the measure of ∠AQB is ______.
