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Evaluate: cot241∘tan249∘-2sin275∘cos215∘ - Mathematics

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Question

Evaluate:

`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`

Evaluate

Solution

`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`

= `[cot(90^circ - 49^circ)]^2/(tan^2 49^circ) - 2 [sin(90^circ - 15^circ)]^2/cos^2 15^circ`

= `tan^2 49^circ/(tan^2 49^circ) - 2 cos^2 15^circ/cos^2 15^circ`

= 1 – 2

= – 1

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Chapter 21: Trigonometrical Identities - Exercise 21 (C) [Page 328]

APPEARS IN

Selina Mathematics [English] Class 10 ICSE
Chapter 21 Trigonometrical Identities
Exercise 21 (C) | Q 5.7 | Page 328
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