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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Find the differential equation of the family of circles passing through the origin and having their centres on the x -axis - Mathematics

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Question

Find the differential equation of the family of circles passing through the origin and having their centres on the x-axis

Sum

Solution

Given the circles centre on x-axis and the circle is passing through the origin.

Let it be (r, 0) and its radius r

Equation of the circle is

(x – a)2 + (y – b)2 = r2

(x – r)2 + (y – 0)2 = r2

x2 – 2xr + r2 + y2 = r2

x2 – 2xr + y2 = r2 – r2

x2 – 2xr + y2 = 0  ........(1)

Differentiating equation (1) with respect to ‘x’, we get

2x – 2r + 2y `("d"y)/("d"x)` = 0 dx

2x + 2y `("d"y)/("d"x)` = 2r

`x + y ("d"y)/("d"x)` = r

Substituting r value in equation (1), we get

`x^2 - 2x(x + y ("d"y)/("d"x)) + y^2` = 0

`x^2 - 2x^2 - 2xy  ("d"y)/("d"x) + y^2` = 0

`- x^2 - 2xy ("d"y)/("d"x) + y^2` = 0

Multiply by '_', we et

`x^2+ 2xy ("d"y)/("d"x) - y^2` = 0

Which is a required differential equation.

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Formation of Differential Equations
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Chapter 10: Ordinary Differential Equations - Exercise 10.3 [Page 154]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 10 Ordinary Differential Equations
Exercise 10.3 | Q 3 | Page 154

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