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Find the value of x, y, and z from the following equation: [x+y25+zxy]=[6258] - Mathematics

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Question

Find the value of x, y, and z from the following equation:

`[(x+y, 2),(5+z, xy)] = [(6,2), (5,8)]`

Sum

Solution

`[(x+y, 2),(5+z, xy)] = [(6,2), (5,8)]`

As the given matrices are equal, their corresponding elements are also equal.

Comparing the corresponding elements, we get:

Now, 5 + z = 5 ⇒ z = 0

Also, x + y = 6

y = 6 - x          .....(i)

and xy = 8           .....(ii)

Solving (i) & (ii), we have x (6 - x) = 8

= 6x - x2 = 8

x2 - 6x + 8 = 0

= (x - 4) (x - 2) = 0

= x = 2, 4

When x = 2, we get y = 4 and when x = 4, we get y = 6 - 4 = 2

Hence, x = 2, y = 4, z = 0 or x = 4, y = 2, z = 0.

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Chapter 3: Matrices - Exercise 3.1 [Page 64]

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NCERT Mathematics [English] Class 12
Chapter 3 Matrices
Exercise 3.1 | Q 6.2 | Page 64

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