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Question
Solution
\[AB = \begin{bmatrix}2 & 4 & - 1 \\ - 1 & 0 & 2\end{bmatrix}\begin{bmatrix}3 & 4 \\ - 1 & 2 \\ 2 & 1\end{bmatrix}\]
\[ \Rightarrow AB = \begin{bmatrix}6 - 4 - 2 & 8 + 8 - 1 \\ - 3 - 0 + 4 & - 4 + 0 + 2\end{bmatrix}\]
\[ \Rightarrow AB = \begin{bmatrix}0 & 15 \\ 1 & - 2\end{bmatrix}\]
\[ \Rightarrow \left( AB \right)^T = \begin{bmatrix}0 & 1 \\ 15 & - 2\end{bmatrix}\]
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