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Question
If a and b are distinct primes such that `root3 (a^6b^-4)=a^xb^(2y),` find x and y.
Solution
Given `root3 (a^6b^-4)=a^xb^(2y)`
`rArr(a^6b^-4)^(1/3)=a^xb^(2y)`
`rArra^(6xx1/3)b^(-4xx1/3)=a^xb^(2y)`
`rArra^2b^(-4/3)=a^xb^(2y)`
⇒ x = 2 and y = -2/3
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