English

If cotθ + tanθ = 2cosecθ, then find the general value of θ. - Mathematics

Advertisements
Advertisements

Question

If cotθ + tanθ = 2cosecθ, then find the general value of θ.

Sum

Solution

Given that: cotθ + tanθ = 2cosecθ

⇒ `costheta/sintheta + sintheta/costheta = 2/sintheta`

⇒ `(cos^2theta + sin^2theta)/(sintheta cos theta) = 2/sintheta`

⇒ `1/(sintheta costheta) = 2/sintheta`

⇒ 2sinθ cosθ = sinθ

⇒ 2sinθ cosθ – sinθ = 0

⇒ sinθ(2cosθ – 1) = 0

⇒ sinθ ≠ 0 or 2cosθ – 1 = 0 or cosθ = `1/2`

⇒ cosθ = `cos  pi/3`

∴ θ = `2"n"pi +- pi/3`

Hence, the general value of θ is `2"n"pi +- pi/3`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Trigonometric Functions - Exercise [Page 54]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 3 Trigonometric Functions
Exercise | Q 17 | Page 54

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Prove that  `2 sin^2  pi/6 + cosec^2  (7pi)/6 cos^2  pi/3 = 3/2`


Prove the following: `cos (pi/4 xx x) cos (pi/4 - y) - sin (pi/4 -  x)sin (pi/4  - y) =  sin (x + y)`


Prove the following:

`cos ((3pi)/4 + x) - cos((3pi)/4 - x) = -sqrt2 sin x`


Prove the following:

`(sin 5x + sin 3x)/(cos 5x + cos 3x) = tan 4x`


Prove the following:

`(sin x - sin 3x)/(sin^2 x - cos^2 x) =  2sin x`


Prove the following:

`tan 4x = (4tan x(1 - tan^2 x))/(1 - 6tan^2 x + tan^4 x)`


Prove that: `(cos x - cosy)^2 + (sin x - sin y)^2 = 4 sin^2  (x - y)/2`


If \[\sin A = \frac{3}{5}, \cos B = - \frac{12}{13}\], where A and B both lie in second quadrant, find the value of sin (A + B).


If \[\sin A = \frac{1}{2}, \cos B = \frac{\sqrt{3}}{2}\], where \[\frac{\pi}{2}\] < A < π and 0 < B < \[\frac{\pi}{2}\], find the following:
tan (A - B)


Evaluate the following:
 cos 80° cos 20° + sin 80° sin 20°


Prove that:

\[\sin\left( \frac{3\pi}{8} - 5 \right)\cos\left( \frac{\pi}{8} + 5 \right) + \cos\left( \frac{3\pi}{8} - 5 \right)\sin\left( \frac{\pi}{8} + 5 \right) = 1\]

 


 If \[\tan A = \frac{5}{6}\text{ and }\tan B = \frac{1}{11}\], prove that \[A + B = \frac{\pi}{4}\].


Prove that:
sin2 (n + 1) A − sin2 nA = sin (2n + 1) A sin A.


Prove that:
\[\frac{\tan \left( A + B \right)}{\cot \left( A - B \right)} = \frac{\tan^2 A - \tan^2 B}{1 - \tan^2 A \tan^2 B}\]


Prove that:
tan 8x − tan 6x − tan 2x = tan 8x tan 6x tan 2x


If tan x + \[\tan \left( x + \frac{\pi}{3} \right) + \tan \left( x + \frac{2\pi}{3} \right) = 3\], then prove that \[\frac{3 \tan x - \tan^3 x}{1 - 3 \tan^2 x} = 1\].


If sin (α + β) = 1 and sin (α − β) \[= \frac{1}{2}\], where 0 ≤ α, \[\beta \leq \frac{\pi}{2}\], then find the values of tan (α + 2β) and tan (2α + β).


Find the maximum and minimum values of each of the following trigonometrical expression:

 12 sin x − 5 cos 


If x cos θ = y cos \[\left( \theta + \frac{2\pi}{3} \right) = z \cos \left( \theta + \frac{4\pi}{3} \right)\]then write the value of \[\frac{1}{x} + \frac{1}{y} + \frac{1}{z}\] 


If tan (A + B) = p and tan (A − B) = q, then write the value of tan 2B


If A + B = C, then write the value of tan A tan B tan C.


If 3 sin x + 4 cos x = 5, then 4 sin x − 3 cos x =


If cos (A − B) \[= \frac{3}{5}\] and tan A tan B = 2, then


Match each item given under column C1 to its correct answer given under column C2.

C1 C2
(a) `(1 - cosx)/sinx` (i) `cot^2  x/2`
(b) `(1 + cosx)/(1 - cosx)` (ii) `cot  x/2`
(c) `(1 + cosx)/sinx` (iii) `|cos x + sin x|`
(d) `sqrt(1 + sin 2x)` (iv) `tan  x/2`

The value of sin(45° + θ) - cos(45° - θ) is ______.


If tanα = `1/7`, tanβ = `1/3`, then cos2α is equal to ______.


3(sinx – cosx)4 + 6(sinx + cosx)2 + 4(sin6x + cos6x) = ______.


Given x > 0, the values of f(x) = `-3cos sqrt(3 + x + x^2)` lie in the interval ______.


In the following match each item given under the column C1 to its correct answer given under the column C2:

Column A Column B
(a) sin(x + y) sin(x – y) (i) cos2x – sin2y
(b) cos (x + y) cos (x – y) (ii) `(1 - tan theta)/(1 + tan theta)`
(c) `cot(pi/4 + theta)` (iii) `(1 + tan theta)/(1 - tan theta)`
(d) `tan(pi/4 + theta)` (iv) sin2x – sin2y

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×