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Question
If xy = 2x – y, then `("d"y)/("d"x)` = ______
Options
`(xlog2 - y)/(xlog2x)`
`(xlog2 + y)/(xlog2x)`
`(xlog2 + x)/(ylog2x)`
`(ylog2 - x)/(xlog2x)`
Solution
If xy = 2x – y, then `("d"y)/("d"x)` =`bbunderline((xlog2 + y)/(xlog2x))`
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