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Question
In the following figure, seg AB is a diameter of the circle, m (arc AKC) = 40°. Find the value of m (arc BMC).
Solution
Seg AB is a diameter
⇒ M (arc ACB) =180° [Angle Made in Semi circle = 180°]
⇒ M (arc AKC) +m (arc BMC) = m (arc ACB) [Arc Addition
Property]
⇒ 40+ m (arc BMC) = 180°
⇒ M (arc BMC) = 180° -40°
⇒ M (arc BMC) =140°
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