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Question
In the given figure; ∠C = 90o and D is mid-point of AC.
Find :
(i) `(tan∠CAB)/ (tan∠CDB)` (ii) `(tan∠ABC)/ (tan∠DBC)`
Solution
Since D is mid-point of AC so AC = 2DC
(i) `(tan∠CAB)/ (tan∠CDB)`
= `("BC"/"AC")/("BC"/"DC")`
= `"BC"/"2 DC"."DC"/"BC"`
= `(1)/(2)`
(ii) `(tan∠ABC)/ (tan∠DBC)`
= `("AC"/"BC")/("DC"/"BC")`
= `"2 DC"/"BC"."BC"/"DC"`
= 2
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