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Prove that the function f given by f(x) = log cos x is strictly decreasing on (0,π2) and strictly increasing on (π2,π) - Mathematics

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Question

Prove that the function f given by f(x) = log cos x is strictly decreasing on `(0, pi/2)` and strictly increasing on `((3pi)/2, 2pi).`

Sum

Solution

Here f(x) = log cos x

`therefore f'(x) = 1/(cos x) (- sin x) = - tan x`

(i) In the interval `(0, pi/2)`, tan x = + ve

∴ f' (x) = - ve

Hence, f is a decreasing function.

(ii) In the interval `(pi/2, pi)`, tan x = - ve

∴ f' (x) = - tan x = - ve

Hence, f is an increasing function.

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Chapter 6: Application of Derivatives - Exercise 6.2 [Page 206]

APPEARS IN

NCERT Mathematics [English] Class 12
Chapter 6 Application of Derivatives
Exercise 6.2 | Q 17 | Page 206

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