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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

Prove the following identities. 1+sinθ1-sinθ+1-sinθ1+sinθ = 2 sec θ - Mathematics

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Question

Prove the following identities.

`sqrt((1 + sin theta)/(1 - sin theta)) + sqrt((1 - sin theta)/(1 + sin theta))` = 2 sec θ

Sum

Solution

`sqrt((1 + sin theta)/(1 - sin theta)) + sqrt((1 - sin theta)/(1 + sin theta))` = 2 sec θ

`sqrt((1 + sin theta)/(1 - sin theta)) = sqrt(((1 + sin theta)(1 + sin theta))/((1 - sin theta)(1 + sin theta))`

= `sqrt((1 + sin theta)^2/(1 - sin^2 theta)`

= `sqrt((1 + sin theta)^2/(cos^2 theta)`

= `(1 + sin theta)/cos theta`

`sqrt(((1 - sin theta))/((1 + sin theta))) = sqrt(((1 - sin theta))/((1 - sin theta)) xx ((1 + sin theta))/((1 - sin theta))`

= `sqrt((1 - sin theta)^2/(1 - sin^2 theta)`

= `sqrt((1- sin theta)^2/(cos^2 theta)) = (1 - sin theta)/cos theta`

L.H.S. = `sqrt((1 + sin theta)/(1 - sin theta)) + sqrt((1 - sin theta)/(1 + sin theta)`

= `(1 + sin theta)/cos theta + (1 - sin theta)/cos theta`

= `(1 + sin theta + 1 - sin theta)/cos theta`

= `2/cos theta`

= 2 sec θ

L.H.S. = R.H.S.

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Chapter 6: Trigonometry - Exercise 6.1 [Page 250]

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Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 6 Trigonometry
Exercise 6.1 | Q 3. (ii) | Page 250
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