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Solutions for Chapter 2: Algebra
Below listed, you can find solutions for Chapter 2 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Business Mathematics and Statistics [English] Class 11 TN Board.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 2 Algebra Exercise 2.1 [Page 29]
Resolve into partial fraction for the following:
`(3x + 7)/(x^2 - 3x + 2)`
Resolve into partial fraction for the following:
`(4x + 1)/((x - 2)(x + 1))`
Resolve into partial fraction for the following:
`1/((x - 1)(x + 2)^2)`
Resolve into partial fraction for the following:
`1/(x^2 - 1)`
Resolve into partial fraction for the following:
`(x - 2)/((x + 2)(x - 1)^2)`
Resolve into partial fraction for the following:
`(2x^2 - 5x - 7)/(x - 2)^3`
Resolve into a partial fraction for the following:
`(x^2 - 6x + 2)/(x^2 (x + 2))`
Resolve into partial fraction for the following:
`(x^2 - 3)/((x + 2)(x^2 + 1))`
Resolve into a partial fraction for the following:
`(x + 2)/((x - 1)(x + 3)^2)`
Resolve into a partial fraction for the following:
`1/((x^2 + 4)(x + 1))`
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 2 Algebra Exercise 2.2 [Page 32]
Find x if `1/(6!) + 1/(7!) = x/(8!)`
Evaluate `("n"!)/("r"!("n" - "r")!)` when n = 5 and r = 2.
If (n+2)! = 60[(n–1)!], find n
How many five digits telephone numbers can be constructed using the digits 0 to 9 If each number starts with 67 with no digit appears more than once?
How many numbers lesser than 1000 can be formed using the digits 5, 6, 7, 8, and 9 if no digit is repeated?
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 2 Algebra Exercise 2.3 [Pages 35 - 36]
If nP4 = 12(nP2), find n.
In how many ways 5 boys and 3 girls can be seated in a row, so that no two girls are together?
How many 6-digit telephone numbers can be constructed with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 if each numbers starts with 35 and no digit appear more than once?
Find the number of arrangements that can be made out of the letters of the word “ASSASSINATION”.
- In how many ways can 8 identical beads be strung on a necklace?
- In how many ways can 8 boys form a ring?
Find the rank of the word ‘CHAT’ in the dictionary.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 2 Algebra Exercise 2.4 [Page 38]
If nPr = 1680 and nCr = 70, find n and r.
Verify that 8C4 + 8C3 = 9C4.
How many chords can be drawn through 21 points on a circle?
How many triangles can be formed by joining the vertices of a hexagon?
Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
If four dice are rolled, find the number of possible outcomes in which atleast one die shows 2.
There are 18 guests at a dinner party. They have to sit 9 guests on either side of a long table, three particular persons decide to sit on one side and two others on the other side. In how many ways can the guests to be seated?
If a polygon has 44 diagonals, find the number of its sides.
In how many ways can a cricket team of 11 players be chosen out of a batch of 15 players?
- There is no restriction on the selection.
- A particular player is always chosen.
- A particular player is never chosen.
A committee of 5 is to be formed out of 6 gents and 4 ladies. In how many ways this can be done when
- atleast two ladies are included.
- atmost two ladies are included.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 2 Algebra Exercise 2.5 [Page 41]
By the principle of mathematical induction, prove the following:
13 + 23 + 33 + ….. + n3 = `("n"^2("n + 1")^2)/4` for all x ∈ N.
By the principle of mathematical induction, prove the following:
1.2 + 2.3 + 3.4 + … + n(n + 1) = `(n(n + 1)(n + 2))/3` for all n ∈ N.
By the principle of mathematical induction, prove the following:
4 + 8 + 12 + ……. + 4n = 2n(n + 1), for all n ∈ N.
By the principle of mathematical induction, prove the following:
1 + 4 + 7 + ……. + (3n – 2) = `("n"(3"n" - 1))/2` for all n ∈ N.
By the principle of mathematical induction, prove the following:
32n – 1 is divisible by 8, for all n ∈ N.
By the principle of mathematical induction, prove the following:
an – bn is divisible by a – b, for all n ∈ N.
By the principle of mathematical induction, prove the following:
52n – 1 is divisible by 24, for all n ∈ N.
By the principle of mathematical induction, prove the following:
n(n + 1) (n + 2) is divisible by 6, for all n ∈ N.
By the principle of mathematical induction, prove the following:
2n > n, for all n ∈ N.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 2 Algebra Exercise 2.6 [Page 45]
Expand the following by using binomial theorem.
(2a – 3b)4
Expand the following by using binomial theorem.
`(x + 1/y)^7`
Expand the following by using binomial theorem.
`(x + 1/x^2)^6`
Evaluate the following using binomial theorem:
(101)4
Evaluate the following using binomial theorem:
(999)5
Find the 5th term in the expansion of (x – 2y)13.
Find the middle terms in the expansion of
`(x + 1/x)^11`
Find the middle terms in the expansion of
`(3x + x^2/2)^8`
Find the middle terms in the expansion of
`(2x^2 - 3/x^3)^10`
Find the term independent of x in the expansion of
`(x^2 - 2/(3x))^9`
Find the term independent of x in the expansion of
`(x - 2/x^2)^15`
Find the term independent of x in the expansion of
`(2x^2 + 1/x)^12`
Prove that the term independent of x in the expansion of `(x + 1/x)^(2n)` is `(1*3*5...(2n - 1)2^n)/(n!)`.
Show that the middle term in the expansion of is (1 + x)2n is `(1*3*5...(2n - 1)2^nx^n)/(n!)`
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 2 Algebra Exercise 2.7 [Pages 45 - 47]
Choose the correct answer
If nC3 = nC2 then the value of nC4 is:
2
3
4
5
The value of n, when np2 = 20 is:
3
6
5
4
The number of ways selecting 4 players out of 5 is
4!
20
25
5
If nPr = 720(nCr), then r is equal to:
4
5
6
7
The possible outcomes when a coin is tossed five times:
25
52
10
`5/2`
The number of diagonals in a polygon of n sides is equal to
nC2
nC2 – 2
nC2 – n
nC2 – 1
The greatest positive integer which divide n(n + 1) (n + 2) (n + 3) for all n ∈ N is:
2
6
20
24
If n is a positive integer, then the number of terms in the expansion of (x + a)n is:
n
n + 1
n - 1
2n
For all n > 0, nC1 + nC2 + nC3 + …… + nCn is equal to:
2n
2n – 1
n2
n2 – 1
The term containing x3 in the expansion of (x – 2y)7 is:
3rd
4th
5th
6th
The middle term in the expansion of `(x + 1/x)^10` is
10C4 `(1/x)`
10C5
10C6
10C7 x2
The constant term in the expansion of `(x + 2/x)^6` is
156
165
162
160
The last term in the expansion of (3 + √2 )8 is:
81
16
8
2
If `(kx)/((x + 4)(2x - 1)) = 4/(x + 4) + 1/(2x - 1)` then k is equal to:
9
11
5
7
The number of 3 letter words that can be formed from the letters of the word ‘NUMBER’ when the repetition is allowed are:
206
133
216
300
The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of three parallel lines is:
18
12
9
6
There are 10 true or false questions in an examination. Then these questions can be answered in
240 ways
120 ways
1024 ways
100 ways
The value of (5C0 + 5C1) + (5C1 + 5C2) + (5C2 + 5C3) + (5C3 + 5C4) + (5C4 + 5C5) is:
26 – 2
25 – 1
28
27
The total number of 9 digit number which has all different digit is:
10!
9!
9 × 9!
10 × 10!
The number of ways to arrange the letters of the word “CHEESE”:
120
240
720
6
Thirteen guests have participated in a dinner. The number of handshakes that happened in the dinner is:
715
78
286
13
The number of words with or without meaning that can be formed using letters of the word “EQUATION”, with no repetition of letters is:
7!
3!
8!
5!
Sum of binomial coefficient in a particular expansion is 256, then number of terms in the expansion is:
8
7
6
9
The number of permutation of n different things taken r at a time, when the repetition is allowed is:
rn
nr
`(n!)/((n - r)!)`
`(n!)/((n + r)!)`
Sum of the binomial coefficients is
2n
n2
2n
n + 17
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 2 Algebra Miscellaneous Problems [Page 47]
Resolve into Partial Fractions:
`(5x + 7)/((x-1)(x+3))`
Resolve into Partial Fractions:
`(x - 4)/(x^2 - 3x + 2)`
Decompose into Partial Fractions:
`(6x^2 - 14x - 27)/((x + 2)(x - 3)^2)`
Decompose into Partial Fractions:
`(5x^2 - 8x + 5)/((x - 2)(x^2 - x + 1))`
Evaluate the following.
`(3! xx 0! + 0!)/(2!)`
Evaluate the following.
`(3! + 1!)/(2^2!)`
Evaluate the following.
`((3!)! xx 2!)/(5!)`
How many code symbols can be formed using 5 out of 6 letters A, B, C, D, E, F so that the letters
- cannot be repeated
- can be repeated
- cannot be repeated but must begin with E
- cannot be repeated but end with CAB.
From 20 raffle tickets in a hat, four tickets are to be selected in order. The holder of the first ticket wins a car, the second a motor cycle, the third a bicycle and the fourth a skateboard. In how many different ways can these prizes be awarded?
In how many different ways, 2 Mathematics, 2 Economics and 2 History books can be selected from 9 Mathematics, 8 Economics and 7 History books?
Let there be 3 red, 2 yellow and 2 green signal flags. How many different signals are possible if we wish to make signals by arranging all of them vertically on a staff?
Find the Co-efficient of x11 in the expansion of `(x + 2/x^2)^17`
Solutions for 2: Algebra
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Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board chapter 2 - Algebra
Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Business Mathematics and Statistics [English] Class 11 TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Business Mathematics and Statistics [English] Class 11 TN Board Tamil Nadu Board of Secondary Education 2 (Algebra) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Business Mathematics and Statistics [English] Class 11 TN Board chapter 2 Algebra are Partial Fractions, Permutations, Combinations, Mathematical Induction, Binomial Theorem.
Using Samacheer Kalvi Business Mathematics and Statistics [English] Class 11 TN Board solutions Algebra exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Samacheer Kalvi Solutions are essential questions that can be asked in the final exam. Maximum Tamil Nadu Board of Secondary Education Business Mathematics and Statistics [English] Class 11 TN Board students prefer Samacheer Kalvi Textbook Solutions to score more in exams.
Get the free view of Chapter 2, Algebra Business Mathematics and Statistics [English] Class 11 TN Board additional questions for Mathematics Business Mathematics and Statistics [English] Class 11 TN Board Tamil Nadu Board of Secondary Education, and you can use Shaalaa.com to keep it handy for your exam preparation.