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![Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board chapter 4 - Trigonometry Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board chapter 4 - Trigonometry - Shaalaa.com](/images/business-mathematics-and-statistics-english-class-11-tn-board_6:5f2b1b2038084cf381bfa42c826a928c.jpg)
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Solutions for Chapter 4: Trigonometry
Below listed, you can find solutions for Chapter 4 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Business Mathematics and Statistics [English] Class 11 TN Board.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 4 Trigonometry Exercise 4.1 [Pages 80 - 81]
Convert the following degree measure into radian measure.
60°
Convert the following degree measure into radian measure.
150°
Convert the following degree measure into radian measure.
240°
Convert the following degree measure into radian measure.
- 320°
Find the degree measure corresponding to the following radian measure.
`pi/8`
Find the degree measure corresponding to the following radian measure.
`(9pi)/5`
Find the degree measure corresponding to the following radian measure.
-3
Find the degree measure corresponding to the following radian measure.
`(11pi)/18`
Determine the quadrant in which the following degree lie.
380°
Determine the quadrant in which the following degree lie.
-140°
Determine the quadrant in which the following degree lie.
1195°
Find the values of the following trigonometric ratio.
sin 300°
Find the values of the following trigonometric ratio.
cos (-210°)
Find the values of the following trigonometric ratio.
sec 390°
Find the values of the following trigonometric ratio.
tan(-855°)
Find the values of the following trigonometric ratio.
cosec 1125°
Prove that:
tan(-225°) cot(-405°) – tan(-765°) cot(675°) = 0.
Prove that:
2 sin2 `pi/6` + cosec2 `(7pi)/6` cos2 `pi/3 = 3/2`
Prove that:
`sec((3pi)/2 - theta) sec(theta - (5pi)/2) + tan((5pi)/2 + theta) tan(theta - (5pi)/2)` = - 1
If A, B, C, D are angles of a cyclic quadrilateral, prove that: cos A + cos B + cos C + cos D = 0.
Prove that:
`(sin(180^circ - theta)cos(90^circ + theta)tan(270^circ - theta)cot(360^circ - theta))/(sin(360^circ - theta)cos(360^circ + theta)sin(270^circ - theta)cosec (-theta))` = -1
Prove that:
`sin theta * cos theta {sin(pi/2 - theta) * "cosec" theta + cos (pi/2 - theta) * sec theta}` = 1
Prove that: cos 510° cos 330° + sin 390° cos 120° = -1.
Prove that:
tan(π + x) cot(x – π) – cos(2π – x) cos(2π + x) = sin2 x.
Prove that:
`(sin(180^circ + "A")cos(90^circ - "A")tan(270^circ - "A"))/(sec(540^circ - "A") cos(360^circ + "A") "cosec"(270^circ + "A"))` = - sin A cos2 A.
If sin θ = `3/5`, tan φ = `1/2 and pi/2` < θ < π < φ < `(3pi)/2,`, then find the value of 8 tan θ – `sqrt5` sec φ.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 4 Trigonometry Exercise 4.2 [Pages 84 - 85]
Find the value of the following:
cosec 15º
Find the value of the following:
sin (-105°)
Find the value of the following:
cot 75°
Find the value of the following:
sin 76° cos 16° – cos 76° sin 16°
Find the value of the following:
`sin pi/4 cos pi/12 + cos pi/4 sin pi/12`
Find the value of the following:
cos 70° cos 10° – sin 70° sin 10°
Find the value of the following:
cos2 15° – sin2 15°
If sin A = `3/5`, 0 < A < `pi/2` and cos B = `(-12)/13`, π < B < `(3pi)/2`, find the values of the following:
- cos(A + B)
- sin(A – B)
- tan(A – B)
If cos A = `13/14` and cos B = `1/7` where A, B are acute angles prove that A – B = `pi/3`
Prove that 2 tan 80° = tan 85° – tan 5°.
If cot α = `1/2`, sec β = `(-5)/3`, where π < α < `(3pi)/2 and pi/2` < β < π, find the value of tan(α + β). State the quadrant in which α + β terminates.
If A + B = 45°, prove that (1 + tan A) (1 + tan B) = 2 and hence deduce the value of tan 22`1/2`.
Prove that:
sin(A + 60°) + sin(A – 60°) = sin A.
Prove that:
tan 4A tan 3A tan A + tan 3A + tan A – tan 4A = 0
If tan θ = 3 find tan 3θ
If sin A = `12/13`, find sin 3A.
If sin A = `3/5`, find the values of cos 3A and tan 3A.
Prove that `(sin ("B - C"))/(cos "B" cos "C") + (sin ("C - A"))/(cos "C" cos "A") + (sin ("A - B"))/(cos "A" cos "B")` = 0
If tan A – tan B = x and cot B – cot A = y prove that cot(A – B) = `1/x + 1/y`.
If sin α + sin β = a and cos α + cos β = b, then prove that cos(α – β) = `(a^2 + b^2 - 2)/2`
Find the value of tan `pi/8`.
If tan α = `1/7`, sin β = `1/sqrt10`. Prove that α + 2β = `pi/4` where 0 < α < `pi/2` and 0 < β < `pi/2`.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 4 Trigonometry Exercise 4.3 [Pages 88 - 89]
Express the following as the sum or difference of sine or cosine:
`sin "A"/8 sin (3"A")/8`
Express the following as the sum or difference of sine or cosine:
cos(60° + A) sin(120° + A)
Express the following as the sum or difference of sine or cosine:
`cos (7"A")/3 sin (5"A")/3`
Express the following as the sum or difference of sine or cosine:
cos 7θ sin 3θ
Express the following as the product of sine and cosine.
sin A + sin 2A
Express the following as the product of sine and cosine.
cos 2A + cos 4A
Express the following as the product of sine and cosine.
sin 6θ – sin 2θ
Express the following as the product of sine and cosine.
cos 2θ – cos θ
Prove that:
cos 20° cos 40° cos 80° = `1/8`
Prove that:
tan 20° tan 40° tan 80° = `sqrt3`.
Prove that:
(cos α – cos β)2 + (sin α – sin β)2 = 4 sin2 `((alpha - beta)/2)`
Prove that:
sin A sin(60° + A) sin(60° – A) = `1/4` sin 3A
Prove that:
sin (A – B) sin C + sin (B – C) sin A + sin(C – A) sin B = 0
Prove that:
2 cos `pi/13` cos \[\frac{9\pi}{13} + \text{cos} \frac{3\pi}{13} + \text{cos} \frac{5\pi}{13}\] = 0
Prove that:
`(cos 2"A" - cos 3"A")/(sin "2A" + sin "3A") = tan "A"/2`
Prove that:
`(cos 7"A" +cos 5"A")/(sin 7"A" −sin 5"A")` = cot A
Prove that cos 20° cos 40° cos 60° cos 80° = `3/16`.
Evaluate-
cos 20° + cos 100° + cos 140°
Evaluate:
sin 50° – sin 70° + sin 10°
If cos A + cos B = `1/2` and sin A + sin B = `1/4`, prove that tan `(("A + B")/2) = 1/2`
If sin(y + z – x), sin(z + x – y), sin(x + y – z) are in A.P, then prove that tan x, tan y and tan z are in A.P.
If cosec A + sec A = cosec B + sec B prove that cot`(("A + B"))/2` = tan A tan B.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 4 Trigonometry Exercise 4.4 [Page 92]
Find the principal value of the following:
`sin^-1 (- 1/2)`
Find the principal value of the following:
tan-1 (-1)
Find the principal value of the following:
cosec-1 (2)
Find the principal value of the following:
`sec^-1 (-sqrt2)`
Prove that:
2 tan-1 (x) = `sin^-1 ((2x)/(1 + x^2))`
Prove that:
`tan^-1 (4/3) + tan^-1 (1/7) = pi/4`
Show that `tan^-1 (1/2) + tan^-1 (2/11) = tan^-1 (3/4)`
Solve `tan^-1 2x + tan^-1 3x = pi/4`
Solve: tan-1 (x + 1) + tan-1 (x – 1) = `tan^-1 (4/7)`
Evaluate:
`cos[tan^-1 (3/4)]`
Evaluate: sin`[1/2 cos^-1 (4/5)]`
Evaluate: `cos (sin^-1 (4/5) + sin^-1 (12/13))`
Prove that `tan^-1 (m/n) - tan^-1 ((m - n)/(m + n)) = pi/4`
Show that `sin^-1 (- 3/5) - sin^-1 (- 8/17) = cos^-1 (84/85)`
Express `tan^-1 [(cos x)/(1 - sin x)], - pi/2 < x < (3pi)/2` in the simplest form.
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 4 Trigonometry Exercise 4.5 [Pages 92 - 94]
Choose the correct answer
The degree measure of `pi/8` is
20°60′
22°30′
22°60′
20°30′
The radian measure of 37°30′ is:
`(5pi)/24`
`(3pi)/24`
`(7pi)/24`
`(9pi)/24`
If tan θ = `1/sqrt5` and θ lies in the first quadrant then cos θ is:
`1/sqrt6`
`(-1)/sqrt6`
`sqrt5/sqrt6`
`(-sqrt5)/sqrt6`
The value of sin 15° is:
`(sqrt3 + 1)/(2sqrt2)`
`(sqrt3 - 1)/(2sqrt2)`
`sqrt3/sqrt2`
`(sqrt3)/(2sqrt2)`
The value of sin (-420°)
`sqrt3/2`
`- sqrt3/2`
`1/2`
`- 1/2`
The value of cos(-480°) is:
`sqrt3`
`- sqrt3/2`
`1/2`
`(-1)/2`
The value of sin 28° cos 17° + cos 28° sin 17°
`1/sqrt2`
1
`(-1)/sqrt2`
0
The value of sin 15° cos 15° is:
1
`1/2`
`sqrt3/2`
`1/4`
The value of sec A sin(270° + A) is:
-1
cos2 A
sec2 A
1
If sin A + cos A = 1 then sin 2A is equal to:
1
2
0
\[\frac{1}{2}\]
The value of cos2 45° – sin2 45° is:
`sqrt3/2`
\[\frac{1}{2}\]
0
`1/sqrt1`
The value of 1 – 2 sin2 45° is:
1
`1/2`
`1/4`
0
The value of 4 cos3 40° – 3 cos 40° is
`sqrt3/2`
`- 1/2`
`1/2`
`1/sqrt2`
The value of `(2 tan 30^circ)/(1 + tan^2 30^circ)` is:
`1/2`
`1/sqrt3`
`sqrt3/2`
`sqrt3`
If sin A = `1/2` then 4 cos3 A – 3 cos A is:
1
0
`sqrt3/2`
`1/sqrt2`
The value of `(3 tan 10^circ - tan^3 10^circ)/(1 - 3 tan^2 10^circ)` is:
`1/sqrt3`
`1/2`
`sqrt3/2`
`1/sqrt2`
The value of cosec-1 `(2/sqrt3)` is:
`pi/4`
`pi/2`
`pi/3`
`pi/6`
sec-1 `(2/3)` + cosec-1 `(2/3)`=
`(- pi)/2`
`pi/2`
π
- π
If α and β be between 0 and `pi/2` and if cos(α + β) = `12/13` and sin (α – β) = `3/5` then sin 2α is:
`16/15`
0
`56/65`
`64/65`
If tan A = `1/2` and tan B = `1/3` then tan(2A + B) is equal to:
1
2
3
4
tan`(pi/4 - x)` is:
`((1 + tan x)/(1 - tan x))`
`((1 - tan x)/(1 + tan x))`
1 - tan x
1 + tan x
`sin (cos^-1 3/5)` is
`3/5`
`5/3`
`4/5`
`5/4`
The value of `1/("cosec" (-45^circ))` is:
`(-1)/sqrt2`
`1/sqrt2`
`sqrt2`
`-sqrt2`
If p sec 50° = tan 50° then p is:
cos 50°
sin 50°
tan 50°
sec 50°
`((cos x)/(cosec x)) - sqrt(1 - sin^2x) sqrt(1 - cos^2 x)` is:
cos2 x – sin2 x
sin2 x – cos2 x
1
0
Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board 4 Trigonometry Miscellaneous Problems [Page 94]
Prove that:
`(cos 4x + cos 3x + cos 2x)/(sin 4x + sin 3x + sin 2x)` = cot 3x
Prove that `sqrt3 "cosec" 20^circ - sin 20^circ` = 4
Prove that cot 4x (sin 5x + sin 3x) = cot x(sin 5x - sin 3x).
If tan x = `3/4` and `pi < x < (3pi)/2`, then find the value of sin `x/2` and cos `x/2`.
Prove that `2 sin^2 (3pi)/4 + 2 cos^2 pi/4 + 2 sec^2 pi/3` = 10
Find the value of sin 75°.
Find the value of tan 15°.
If sin A = `1/3`, sin B = `1/4` then find the value of sin (A + B) where A and B are acute angles.
Show that `cos^-1 (12/13) + sin^-1 (3/5) = sin^-1 (56/65)`
If cos (α + β) = `4/5` and sin (α - β) = `5/13` where (α + β) and (α - β) are acute, then find tan 2α.
Express `tan^-1 ((cos x - sin x)/(cos x + sin x))`, 0 < x < π in the simplest form.
Solutions for 4: Trigonometry
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Samacheer Kalvi solutions for Business Mathematics and Statistics [English] Class 11 TN Board chapter 4 - Trigonometry
Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Business Mathematics and Statistics [English] Class 11 TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Business Mathematics and Statistics [English] Class 11 TN Board Tamil Nadu Board of Secondary Education 4 (Trigonometry) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Business Mathematics and Statistics [English] Class 11 TN Board chapter 4 Trigonometry are Trigonometric Ratios, Trigonometric Ratios of Compound Angles, Transformation Formulae, Inverse Trigonometric Functions.
Using Samacheer Kalvi Business Mathematics and Statistics [English] Class 11 TN Board solutions Trigonometry exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Samacheer Kalvi Solutions are essential questions that can be asked in the final exam. Maximum Tamil Nadu Board of Secondary Education Business Mathematics and Statistics [English] Class 11 TN Board students prefer Samacheer Kalvi Textbook Solutions to score more in exams.
Get the free view of Chapter 4, Trigonometry Business Mathematics and Statistics [English] Class 11 TN Board additional questions for Mathematics Business Mathematics and Statistics [English] Class 11 TN Board Tamil Nadu Board of Secondary Education, and you can use Shaalaa.com to keep it handy for your exam preparation.