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A = [cosθ-sinθ-sinθ-cosθ] then find A−1 - Mathematics and Statistics

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प्रश्न

A = `[(cos theta, - sin theta),(-sin theta, -cos theta)]` then find A−1 

योग

उत्तर

|A| = `|(cos theta, - sin theta),(-sin theta, - cos theta)|`

= – cos2θ – sin2θ

= –1 ≠ 0

∴ A–1 exists.

A11 = (–1)1+1 M11 = M11 = – cos θ

A12 = (–1)1+2 M12 = – M12 = sin θ

A21 = (–1)2+1 M21 = – M21 = sin θ

A22 = (–1)2+2 M22 = M22 = cos θ

∴ adj (A) = `[(- cos theta, sin theta),(sin theta, cos theta)]^"T"`

= `[(- cos theta, sin theta),(sin theta, cos theta)]`

A−1 = `1/|"A"|` adj (A)

= `[(cos theta, -sin theta),(-sin theta, -cos theta)]`

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