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प्रश्न
Evaluate the following:
`tan^-1(tan (5pi)/6)+cos^-1{cos((13pi)/6)}`
उत्तर
`tan^-1(tan (5pi)/6)+cos^-1{cos((13pi)/6)}`
`=tan^-1{tan(pi-(5pi)/6)}+cos^-1{cos(2pi+pi/6)}`
`=tan^-1{-tan(pi/6)}+cos^-1{cos(pi/6)}`
`=-tan^-1{tan(pi/6)}+cos^-1{cos(pi/6)}`
`=-pi/6+pi/6`
= 0
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