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प्रश्न
Find the principal value of `cos^(-1) (-1/2)`
उत्तर
y `"cos"^-1 (-1/2)`
`Rightarrow "cos y" = -1/2 = -"cos" pi/3 = "cos" (pi - pi/3)`
We know that the range of the principal value branch of cos−1 is [0, π] and `cos((2pi)/3) = 1/2`
Therefore, the principal value of `cos^(-1) (-1/2)` is `(2pi)/3`
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