हिंदी

∫f′(x)f(x)dx = ______ + c. - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

`int (f^'(x))/(f(x))dx` = ______ + c.

रिक्त स्थान भरें

उत्तर

`int (f^'(x))/(f(x))dx` = log f'(x) + c.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2024-2025 (March) Model set 2 by shaalaa.com

संबंधित प्रश्न

Integrate the functions:

`xsqrt(x + 2)`


Integrate the functions:

`(sin x)/(1+ cos x)^2`


Write a value of

\[\int x^2 \sin x^3 \text{ dx }\]

Write a value of

\[\int\frac{a^x}{3 + a^x} \text{ dx}\]

Write a value of\[\int e^x \left( \frac{1}{x} - \frac{1}{x^2} \right) dx\] .


Write a value of\[\int\sqrt{4 - x^2} \text{ dx }\]


Evaluate:  \[\int\frac{x^3 - 1}{x^2} \text{ dx}\]


The value of \[\int\frac{\cos \sqrt{x}}{\sqrt{x}} dx\] is


\[\int x \sin^3 x\ dx\]

Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`


Integrate the following functions w.r.t. x : `(3e^(2x) + 5)/(4e^(2x) - 5)`


Integrate the following functions w.r.t. x : `int (1)/(4 - 5cosx).dx`


Choose the correct option from the given alternatives : 

`int (1 + x + sqrt(x + x^2))/(sqrt(x) + sqrt(1 + x))*dx` =


Choose the correct options from the given alternatives :

`int sqrt(cotx)/(sinx*cosx)*dx` =


Integrate the following with respect to the respective variable : `(x - 2)^2sqrt(x)`


Integrate the following w.r.t.x : `(3x + 1)/sqrt(-2x^2 + x + 3)`


Evaluate the following.

`int 1/(sqrt(3"x"^2 + 8))` dx


Evaluate `int (5"x" + 1)^(4/9)` dx


`int cos sqrtx` dx = _____________


`int (2(cos^2 x - sin^2 x))/(cos^2 x + sin^2 x)` dx = ______________


`int (log x)/(log ex)^2` dx = _________


`int sin^-1 x`dx = ?


`int "dx"/((sin x + cos x)(2 cos x + sin x))` = ?


`int_1^3 ("d"x)/(x(1 + logx)^2)` = ______.


If `int x^3"e"^(x^2) "d"x = "e"^(x^2)/2 "f"(x) + "c"`, then f(x) = ______.


Evaluate `int(5x^2-6x+3)/(2x-3) dx`


Evaluate `int(1+x+x^2/(2!))dx`


Evaluate `int(5x^2-6x+3)/(2x-3)dx`


Evaluate `int1/(x(x - 1))dx`


If f'(x) = 4x3 – 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×