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Find the Following Product: ( 3 X − 5 Y ) ( 9 X 2 + 25 Y 2 + 15 X Y ) - Mathematics

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प्रश्न

Find the following product:

\[\left( \frac{3}{x} - \frac{5}{y} \right) \left( \frac{9}{x^2} + \frac{25}{y^2} + \frac{15}{xy} \right)\]

संक्षेप में उत्तर

उत्तर

Given \[\left( \frac{3}{x} - \frac{5}{y} \right) \left( \frac{9}{x^2} + \frac{25}{y^2} + \frac{15}{xy} \right)\]

We shall use the identity  `(a-b)(a^2 + ab+ b^2) = a^3 - b^3`

We can rearrange the  ` (3/5 - 5/y) (9^2/x^2 + 25/y^2 + 15/(xy))`as

` = ((3/x - 5/y) ((3/x)^2 + (5/y)^2  + (3/x)(5/y))`

` = (3/x)^3 - (5/y)^3 `

\[= \left( \frac{3}{x} \right) \times \left( \frac{3}{x} \right) \times \left( \frac{3}{x} \right) - \left( \frac{5}{y} \right) \times \left( \frac{5}{y} \right) \times \left( \frac{5}{y} \right)\]

\[ = \frac{27}{x^3} - \frac{125}{y^3}\]

Hence the Product value of `(3/x - 5/y) (9^2/x^2 + 25/y^3 + 15/(xy))`is  `27/x^3 - 125/y^3`.

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अध्याय 4: Algebraic Identities - Exercise 4.4 [पृष्ठ २४]

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आरडी शर्मा Mathematics [English] Class 9
अध्याय 4 Algebraic Identities
Exercise 4.4 | Q 1.05 | पृष्ठ २४

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