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Prove That: Cos 2 π 8 + Cos 2 3 π 8 + Cos 2 5 π 8 + Cos 2 7 π 8 = 2 - Mathematics

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प्रश्न

Prove that: \[\cos^2 \frac{\pi}{8} + \cos^2 \frac{3\pi}{8} + \cos^2 \frac{5\pi}{8} + \cos^2 \frac{7\pi}{8} = 2\]

संख्यात्मक

उत्तर

\[LHS = \cos^2 \frac{\pi}{8} + \cos^2 \frac{3\pi}{8} + \cos^2 \frac{5\pi}{8} + \cos^2 \frac{7\pi}{8}\]

\[ = \cos^2 \frac{\pi}{8} + \cos^2 \frac{3\pi}{8} + \cos^2 \left( \pi - \frac{3\pi}{8} \right) + \cos^2 \left( \pi - \frac{\pi}{8} \right)\]

\[ = \cos^2 \frac{\pi}{8} + \cos^2 \frac{3\pi}{8} + \left\{ - \cos\left( \frac{3\pi}{8} \right) \right\}^2 + \left\{ - \cos\left( \frac{\pi}{8} \right) \right\}^2\]

\[= \cos^2 \frac{\pi}{8} + \cos^2 \frac{3\pi}{8} + \cos^2 \frac{3\pi}{8} + \cos^2 \frac{\pi}{8}\]

\[ = 2\left( \cos^2 \frac{\pi}{8} + \cos^2 \frac{3\pi}{8} \right)\]

\[ = 2\left\{ \cos^2 \frac{\pi}{8} + \cos^2 \left( \frac{\pi}{2} - \frac{\pi}{8} \right) \right\}\]

\[ = 2\left( \cos^2 \frac{\pi}{8} + \sin^2 \frac{\pi}{8} \right)\]

\[ = 2 = RHS\]

\[\text{ Hence proved } .\]

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.1 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.1 | Q 9 | पृष्ठ २८

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