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Prove the following: cos(π+x)cos(-x)sin(π-x)cos(π2+x)= cot2x - Mathematics

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प्रश्न

Prove the following:

cos(π+x)cos(-x)sin(π-x)cos(π2+x)= cot2x

योग

उत्तर

L.H.S. = cos(π+x)cos(-x)sin(π-x)cos(π2+x)

Now using sin(π-x)=sinx,cos(π2+x)=-sinx

L.H.S. = -cosx×cosxsinx (- sin×)

= cos2xsin2x=(cosxsinx)2

= cot2×

= R.H.S.

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अध्याय 3: Trigonometric Functions - Exercise 3.3 [पृष्ठ ७३]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
Exercise 3.3 | Q 8 | पृष्ठ ७३

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