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प्रश्न
Find the value of x in the following :
tan 3x = sin 45º cos 45º + sin 30º
उत्तर १
tan 3x = sin 45º cos 45º + sin 30º
`\Rightarrow tan3x=\frac{1}{\sqrt{2}}\times\frac{1}{\sqrt{2}}+\frac{1}{2}`
`\Rightarrow tan3x=\frac{1}{2}+\frac{1}{2} `
⇒ tan 3x = 1
⇒ tan 3x = tan 45º
⇒ 3x = 45º ⇒ x = 15º
उत्तर २
`tan x= 1/sqrt2 . 1.sqrt2 + 1/2` `[∵ sin 45^@ = 1/sqrt2 cos 45^@ = 1/sqrt2 sin 30^@ = 1/2]`
`tan x = 1/2 + 1/2`
tan x = 1
`tan x = tan 45^@`
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