Advertisements
Advertisements
प्रश्न
In the figure, point Q is the
point of contact. If PQ = 12,
PR = 8 then find PS.
उत्तर
In figure, PQ = 12, PR = 8
PQ2 = PR × PS ............ (Tangent secant theorem)
∴ 122 = 8 × PS
∴ 144 = 8 × PS
∴ PS =
∴ PS = 18
APPEARS IN
संबंधित प्रश्न
In Fig. 7, two equal circles, with centres O and O’, touch each other at X. OO’ produced meets the circle with centre O’ at A. AC is tangent to the circle with centre O, at the point C. O’D is perpendicular to AC. Find the value of
A tangent to a circle intersects it in ______ point (s).
The given figure shows a circle with centre O and BCD is tangent to it at C. Show that : ∠ACD + ∠BAC = 90°.
In Fig. 1, AOB is a diameter of a circle with centre O and AC is a tangent to the circle at A. If ∠BOC = 130°, the find ∠ACO.
In fig. 5 is a chord AB of a circle, with centre O and radius 10 cm, that subtends a right angle at the centre of the circle. Find the area of the minor segment AQBP. Hence find the area of major segment ALBQA. (use π = 3.14)
In Fig.2, a circle with centre O is inscribed in a quadrilateral ABCD such that, it touches the sides BC, AB, AD and CD at points P, Q, R and S respectively, If AB = 29 cm, AD = 23 cm, ∠B = 90° and DS = 5 cm, then the radius of the circle (in cm.) is:
In Figure 1, AP, AQ and BC are tangents to the circle. If AB = 5 cm, AC = 6 cm and BC
= 4 cm, then the length of AP (in cm) is
In the given figure AC is a tangent to the circle with centre O.
If ∠ADB = 55° , find x and y. Give reasons for your answers.
A chord of a length 16.8 cm is at a distance of 11.2 cm from the centre of a circle . Find the length of the chord of the same circle which is at a distance of 8.4 cm from the centre.
In the given figure, diameter AB and chord CD of a circle meet at P. PT is a tangent to the circle at T. CD = 7.8 cm, PD = 5 cm, PB = 4 cm. Find AB.
ABC is a right triangle with angle B = 90º. A circle with BC as diameter meets by hypotenuse AC at point D. Prove that: BD2 = AD × DC.
In a square ABCD, its diagonal AC and BD intersect each other at point O. The bisector of angle DAO meets BD at point M and bisector of angle ABD meets AC at N and AM at L. Show that - ∠ BAM = ∠ BMA
Two equal chords AB and CD of a circle with center O, when produced meet at a point E, as shown in Fig. Prove that BE = DE and AE = CE.
In the figure given below, PT is a tangent to the circle. Find PT if AT = 16 cm and AB = 12 cm.
In figure, if ∠AOB = 125°, then ∠COD is equal to ______.
At one end A of a diameter AB of a circle of radius 5 cm, tangent XAY is drawn to the circle. The length of the chord CD parallel to XY and at a distance 8 cm from A is ______
In the given figure, XAY is a tangent to the circle centered at O. If ∠ABO = 40°, then find ∠BAY and ∠AOB.
In the given figure O, is the centre of the circle. CE is a tangent to the circle at A. If ∠ABD = 26° find:
- ∠BDA
- ∠BAD
- ∠CAD
- ∠ODB
In the given figure, QR is a common tangent to the two given circles touching externally at A. The tangent at A meets QR at P. If AP = 4.2 cm, then the length of QR is ______.
