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The Slope of the Tangent to the Curve X = T2 + 3t – 8, Y = 2t2 – 2t – 5 at the Point (2,– 1) is - Mathematics

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प्रश्न

The slope of the tangent to the curve x = t2 + 3t – 8, y = 2t2 – 2t – 5 at the point (2,– 1) is

(A) `22/7`

(B) `6/7`

(C) `7/6`

(D) `(-6)/7`

उत्तर

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पाठ 6: Application of Derivatives - Exercise 6.6 [पृष्ठ २४३]

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एनसीईआरटी Mathematics [English] Class 12
पाठ 6 Application of Derivatives
Exercise 6.6 | Q 20 | पृष्ठ २४३

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