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प्रश्न
What is the value of \[\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}\]
उत्तर
We have,
`sin^2 θ+1/(1+tan^2θ)= sin^2θ+1/(sqc^2θ)`
=` sin^2θ+(1/secθ)^2`
=` sin^2 θ+cos^2θ`
=` 1`
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