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Question
Answer the following:
Show that, `log ("a"^2/"bc") + log ("b"^2/"ca") + log ("c"^2/"ab")` = 0
Solution
L.H.S. = `log ("a"^2/"bc") + log ("b"^2/"ca") + log ("c"^2/"ab")`
= `log ("a"^2/"bc" xx "b"^2/"ca" xx "c"^2/"ab")`
= `log(("a"^2"b"^2"c"^2)/("a"^2"b"^2"c"^2))`
= log 1
= 0
= R.H.S.
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