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Check the injectivity and surjectivity of the following function. f : Z → Z given by f(x) = x2 - Mathematics and Statistics

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Question

Check the injectivity and surjectivity of the following function.

f : Z → Z given by f(x) = x2 

Sum

Solution

f : Z → Z given by f(x) = x2 

f(2) = 22 = 4 and f(– 2) = (– 2)2 = 4

∴ f(2) = f(– 2) but 2 ≠ – 2

∴ f is not injective

2 ∈ Z but there is no x ∈ Z such that 2 = f(x) = x2

∴ f is not surjective

∴ f is neither injective nor surjective.

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Chapter 6: Functions - Exercise 6.1 [Page 118]

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