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Question
Choose the correct alternative from the following.
`int (("e"^"2x" + "e"^"-2x")/"e"^"x") "dx"` =
Options
`"e"^"x" - 1/(3"e"^"3x")` + c
`"e"^"x" + 1/(3"e"^"3x")` + c
`"e"^"-x" + 1/(3"e"^"3x")` + c
`"e"^"-x" + 1/(3"e"^"3x") + "c"`
Solution
`"e"^"x" - 1/(3"e"^"3x")` + c
Explanation:
`int (("e"^"2x" + "e"^"-2x")/"e"^"x") "dx" = int ("e"^"x" + "e"^(-3"x"))` dx
`= "e"^"x" - 1/3 "e"^(-3"x") + "c"`
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