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Fill in the blank : ∫491x⋅dx = _______ - Mathematics and Statistics

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Question

Fill in the blank : `int_4^9 (1)/sqrt(x)*dx` = _______

Fill in the Blanks

Solution

Let I = `int_4^9 (1)/sqrt(x)*dx`

= `int_4^9x^(1/2)*dx = [(x^(1/2))/(1/2)]_4^9`

= `2[sqrt(x)]_4^9`

= `2(sqrt(9) - sqrt(4))`

= 2 (3 – 2)
∴ I = 2.

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Fundamental Theorem of Integral Calculus
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Chapter 6: Definite Integration - MISCELLANEOUS EXERCISE - 6 [Page 149]

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Balbharati Mathematics and Statistics 1 (Commerce) [English] 12 Standard HSC Maharashtra State Board
Chapter 6 Definite Integration
MISCELLANEOUS EXERCISE - 6 | Q II) 5) | Page 149
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