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Question
Solve the following : `int_0^9 (1)/(1 + sqrt(x))*dx`
Solution
Let I = `int_0^9 (1)/(1 + sqrt(x))*dx`
Put `1 + sqrt(x)` = t
∴ x = (t – 1)2
∴ dx = 2(t – 1)dt
When x = 0, t = 1 + 0 = 1
When x = 9, t = `1 + sqrt(9)`
= 1 + 3 = 4
∴ I = `int_1^4 (2(t - 1))/"t"*"dt"`
= `2int_1^4(1 - 1/"t")*"dt"`
= `2]"t" - log|"t"|]_1^4`
= 2 [(4 – log |4|) – (1 – log |1|)]
= 2 [4 – log 4 – (1 – 0)]
= 2 [4 – log 22 – 1)
= 2 (3 – 2log 2)
∴ I = 6 – 4 log 2.
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