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Question
Evaluate the following : `int_0^3 x^2(3 - x)^(5/2)*dx`
Solution
Let I = `int_0^3 x^2(3 - x)^(5/2)*dx`
We use the property `int_0^a f(x)*dx = int_0^a f(a - x)*dx`
Here, a = 3
Hence in I, changing x to 3 – x, we get
I = `int_0^3 (3 - x)^2 [3 - (3 - x)]^(5/2)*dx`
= `int_0^3 (9 - 6x + x^2)x^(5/2)*dx`
= `int_0^3 [9x^(5/2) - 6x^(7/2) + x^(9/2)]*dx`
= `9 int_0^3 x^(5/2)*dx - 6int_0^3 x^(7/2)*dx + int_0^3 x^(9/2)*dx`
= `9[(x^(7/2))/(7/2)]_0^3 - 6[(x^(9/2))/(9/2)]_0^3 + 9[(x^(11/2))/(11/2)]_0^3`
= `9[(2.3^(7/2))/7 - 0] - 6[(2.3^(9/2))/9 - 0] + [2/11*3^(11/2) - 0]`
= `(18)/(7) 3^(7/2) - (2.6)/9*3^(7/2)*3 + 2/11*3^(7/2)*3^2`
= `2(3)^(7/2)[9/7 - 2 + 9/11]`
= `2(3)^(7/2)[(99 - 154 + 63)/77]`
= `2(3)^(7/2) xx 8/77`
= `16/77(3)^(7/2)`.
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