English

If α, β Are Roots of the Equation 4 X 2 + 3 X + 7 = 0 , Then 1 / α + 1 / β is Equal to - Mathematics

Advertisements
Advertisements

Question

If α, β are roots of the equation \[4 x^2 + 3x + 7 = 0, \text { then } 1/\alpha + 1/\beta\] is equal to

Options

  • 7/3

  • −7/3

  • 3/7

  • -3/7

MCQ

Solution

−3/7

Given equation: 

\[4 x^2 + 3x + 7 = 0\]

Also, 

\[\alpha\] and \[\beta\] are the roots of the equation.

Sum of the roots = \[\alpha + \beta = \frac{- \text { Coefficient of }x}{\text { Coefficient of } x^2} = - \frac{3}{4}\]

Product of the roots = \[\alpha\beta = \frac{\text { Constant term }}{\text { Coefficient of  }x^2} = \frac{7}{4}\]

  ∴  \[\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha\beta} = \frac{- \frac{3}{4}}{\frac{7}{4}} = - \frac{3}{7}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 14: Quadratic Equations - Exercise 14.4 [Page 16]

APPEARS IN

RD Sharma Mathematics [English] Class 11
Chapter 14 Quadratic Equations
Exercise 14.4 | Q 4 | Page 16

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Solve the equation x2 + 3x + 9 = 0


Solve the equation –x2 + x – 2 = 0


Solve the equation  `x^2 + x/sqrt2 + 1 = 0`


Solve the equation `3x^2 - 4x + 20/3 = 0`


Solve the equation   `x^2 -2x + 3/2 = 0`  


\[x^2 - 4x + 7 = 0\]


\[x^2 + 2x + 5 = 0\]


\[21 x^2 - 28x + 10 = 0\]


\[13 x^2 + 7x + 1 = 0\]


Solving the following quadratic equation by factorization method:

\[x^2 - \left( 2\sqrt{3} + 3i \right) x + 6\sqrt{3}i = 0\]


Solve the following quadratic equation:

\[x^2 - \left( 5 - i \right) x + \left( 18 + i \right) = 0\]


Solve the following quadratic equation:

\[x^2 - \left( 2 + i \right) x - \left( 1 - 7i \right) = 0\]


Solve the following quadratic equation:

\[i x^2 - 4 x - 4i = 0\]


Solve the following quadratic equation:

\[x^2 - x + \left( 1 + i \right) = 0\]


Solve the following quadratic equation:

\[x^2 - \left( 3\sqrt{2} - 2i \right) x - \sqrt{2} i = 0\]


Solve the following quadratic equation:

\[2 x^2 - \left( 3 + 7i \right) x + \left( 9i - 3 \right) = 0\]


If a and b are roots of the equation \[x^2 - px + q = 0\], than write the value of \[\frac{1}{a} + \frac{1}{b}\].


If the difference between the roots of the equation \[x^2 + ax + 8 = 0\] is 2, write the values of a.


Write roots of the equation \[(a - b) x^2 + (b - c)x + (c - a) = 0\] .


If α, β are roots of the equation \[x^2 + lx + m = 0\] , write an equation whose roots are \[- \frac{1}{\alpha}\text { and } - \frac{1}{\beta}\].


If α, β are roots of the equation \[x^2 - a(x + 1) - c = 0\] then write the value of (1 + α) (1 + β).


The complete set of values of k, for which the quadratic equation  \[x^2 - kx + k + 2 = 0\] has equal roots, consists of


The number of solutions of `x^2 + |x - 1| = 1` is ______. 


The value of a such that  \[x^2 - 11x + a = 0 \text { and } x^2 - 14x + 2a = 0\] may have a common root is


The values of k for which the quadratic equation \[k x^2 + 1 = kx + 3x - 11 x^2\] has real and equal roots are


If one root of the equation \[x^2 + px + 12 = 0\] while the equation \[x^2 + px + q = 0\] has equal roots, the value of q is


The set of all values of m for which both the roots of the equation \[x^2 - (m + 1)x + m + 4 = 0\] are real and negative, is


The number of roots of the equation \[\frac{(x + 2)(x - 5)}{(x - 3)(x + 6)} = \frac{x - 2}{x + 4}\] is 


If α and β are the roots of \[4 x^2 + 3x + 7 = 0\], then the value of \[\frac{1}{\alpha} + \frac{1}{\beta}\] is


If the difference of the roots of \[x^2 - px + q = 0\]  is unity, then

 

The least value of which makes the roots of the equation  \[x^2 + 5x + k = 0\]  imaginary is


The equation of the smallest degree with real coefficients having 1 + i as one of the roots is


If 1 – i, is a root of the equation x2 + ax + b = 0, where a, b ∈ R, then find the values of a and b.


Show that `|(z - 2)/(z - 3)|` = 2 represents a circle. Find its centre and radius.


If `|(z - 2)/(z + 2)| = pi/6`, then the locus of z is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×