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Question
The values of x satisfying log3 \[( x^2 + 4x + 12) = 2\] are
Options
2, −4
1, −3
−1, 3
−1, −3
Solution
−1, −3 The given equation is \[\log_3 ( x^2 + 4x + 12) = 2\] .
\[\Rightarrow x^2 + 4x + 12 = 3^2 = 9\]
\[ \Rightarrow x^2 + 4x + 3 = 0\]
\[ \Rightarrow \left( x + 1 \right)\left( x + 3 \right) = 0\]
\[ \Rightarrow x = - 1, - 3\]
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