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Question
If O is the origin, OP = 3 with direction ratios proportional to −1, 2, −2 then the coordinates of P are
Options
(−1, 2, −2)
(1, 2, 2)
(−1/9, 2/9, −2/9)
(3, 6, −9)
Solution
(−1, 2,−2)
Let the coordinates of P be (x, y, z). Then,
Direction ratios of OP= Coordinates of P− Coordinates of O
−1, 2, 2 = (x−0), (y−0), (z−0)
Thus, coordinates of P are (−1, 2,−2).
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