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If sinθ + cosθ = 1, then find the general value of θ. - Mathematics

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Question

If sinθ + cosθ = 1, then find the general value of θ.

Sum

Solution

Given, sinθ + cosθ = 1

On dividing both the sides by `sqrt2`,

`sintheta/sqrt2 + costheta/sqrt2 = 1/sqrt2`

⇒ `cos(theta - pi/4) = cos  pi/4`

⇒ `theta - pi/4 = pi/4`

We know that, θ = 2nπ ± α when cosθ = cosα

⇒ `theta - pi/4 = 2npi ± pi/4, n ∈ z`

⇒ `theta = 2npi ± pi/4 + pi/4`

Taking the positive sign,

⇒ `theta = 2npi + pi/4 + pi/4`

⇒ `theta = 2npi + pi/2`

Taking the Negative sign,

⇒ `theta = 2npi - pi/4 + pi/4`

⇒ θ = 2nπ, n ∈ z

So, the general value is `theta = 2npi + pi/2` and θ = 2nπ.

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Chapter 3: Trigonometric Functions - Exercise [Page 53]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 3 Trigonometric Functions
Exercise | Q 15 | Page 53

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