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Question
If x and y are connected parametrically by the equation, without eliminating the parameter, find `dy/dx.`
x = a cos θ, y = b cos θ
Solution
Given, x = a cos θ and y = b cos θ
Differentiating both sides with respect to `theta`,
`dx/(d theta) = - a sin theta`
`dy/(d theta) = - b sin theta`
`dy/dx = (dy/(d theta))/(dx/(d theta))`
`= (- b sin theta)/(- a sin theta)`
` = b/a`
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