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If x and y are connected parametrically by the equation, without eliminating the parameter, find dydx. x = a sec θ, y = b tan θ - Mathematics

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Question

If x and y are connected parametrically by the equation, without eliminating the parameter, find `dy/dx.`

x = a sec θ, y = b tan θ

Sum

Solution

Given, x = a sec θ  and y = b tan θ.

Differentiating both sides with respect to θ,

`dx/(d theta) = a sec θ tan θ ` and `dy/(d theta) = b sec^2 θ`

`therefore dy/dx = (dy/(d theta))/(dx/(d theta))`

`= (b sec^2 theta)/(a sec theta tan theta) = (b sec theta)/(a tan theta)`

`= b/a  sec theta cot theta`

`= b/a xx 1/(cos theta) * (cos theta)/(sin theta)`

`= b/a xx 1/(sin theta)`

`= b/a  cosec  theta`

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Chapter 5: Continuity and Differentiability - Exercise 5.6 [Page 181]

APPEARS IN

NCERT Mathematics [English] Class 12
Chapter 5 Continuity and Differentiability
Exercise 5.6 | Q 9 | Page 181

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