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Question
In fig., line BC || line DE, AB = 2, BD = 3, AC = 4 and CE = x, then find the value of x
Solution
In ΔADE,
line BC || seg DE ......[Given]
∴ by Basic proportionality theorem
∴ `"AB"/"BD" = "AC"/"CE"`
∴ `2/3 = 4/x` ......[Given]
∴ x = `4 xx 3/2`
∴ x = 2 × 3
∴ x = 6
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