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Question
In the given figure, PT ∥ QR and QT ∥ RS. Show that: area of ΔPQR = area of ΔTQS.
*Question modified
Solution
Joining TR, we get
ΔPQR and ΔQTR are on the same base QR and between the same parallel lines QR and PT.
∴ A(ΔPQR) = A(ΔQTR) ....(i)
ΔQTR and ΔTQS are on the same base QT and between the same parallel lines QT and RS.
∴ A(ΔQRT) = A(ΔTQS) ....(ii)
From (i) and (ii), we get
A(ΔPQR) = A(ΔTQS).
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