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Show that (1xx2^2 + 2xx3^2 + ...+Nxx(N+1)^2)/(1^2 Xx 2 + 2^2 Xx3 + ... + N^2xx (N+1)) = (3n + 5)/(3n + 1) - Mathematics

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Question

Show that  `(1xx2^2 + 2xx3^2 + ...+nxx(n+1)^2)/(1^2 xx 2 + 2^2 xx3 + ... + n^2xx (n+1))` = `(3n + 5)/(3n + 1)`

Solution

nth term of the numerator = n(n + 1)2 = n3 + 2n2 + n

nth term of the denominator = n2(n + 1) = n3 + n2

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Chapter 9: Sequences and Series - Miscellaneous Exercise [Page 200]

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NCERT Mathematics [English] Class 11
Chapter 9 Sequences and Series
Miscellaneous Exercise | Q 26 | Page 200

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