English

If N ∑ R = 1 R = 55 , Find N ∑ R = 1 R 3 . - Mathematics

Advertisements
Advertisements

Question

If \[\sum^n_{r = 1} r = 55, \text{ find }  \sum^n_{r = 1} r^3\] .

 

Solution

\[\sum^n_{r = 1} r^3 = 1^3 + 2^3 + 3^3 + . . . + n^3 \]

\[ = \left[ \frac{n\left( n + 1 \right)}{2} \right]^2 \]

\[ = \left[ \sum^n_{r = 1} r \right]^2 \]

\[ = \left[ 55 \right]^2 \]

\[ = 3025\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 21: Some special series - Exercise 21.3 [Page 19]

APPEARS IN

RD Sharma Mathematics [English] Class 11
Chapter 21 Some special series
Exercise 21.3 | Q 4 | Page 19

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the sum to n terms of the series 1 × 2 + 2 × 3 + 3 × 4 + 4 × 5 + …


Find the sum to n terms of the series 1 × 2 × 3 + 2 × 3 × 4 + 3 × 4 × 5 + …


Find the sum to n terms of the series 3 × 12 + 5 × 22 + 7 × 32 + …


Find the sum to n terms of the series `1/(1xx2) + 1/(2xx3)+1/(3xx4)+ ...`


Find the sum to n terms of the series 3 × 8 + 6 × 11 + 9 × 14 +…


Find the sum to n terms of the series 12 + (12 + 22) + (12 + 22 + 32) + …


Find the sum to n terms of the series whose nth term is given by n (n + 1) (n + 4).


Show that  `(1xx2^2 + 2xx3^2 + ...+nxx(n+1)^2)/(1^2 xx 2 + 2^2 xx3 + ... + n^2xx (n+1))` = `(3n + 5)/(3n + 1)`


22 + 42 + 62 + 82 + ...


1.2.4 + 2.3.7 +3.4.10 + ...


1 + (1 + 2) + (1 + 2 + 3) + (1 + 2 + 3 + 4) + ...


1 × 2 + 2 × 3 + 3 × 4 + 4 × 5 + ...


3 × 12 + 5 ×22 + 7 × 32 + ...


Find the sum of the series whose nth term is:

n3 − 3n


Find the sum of the series whose nth term is:

(2n − 1)2


Find the 20th term and the sum of 20 terms of the series 2 × 4 + 4 × 6 + 6 × 8 + ...


Write the sum of the series 2 + 4 + 6 + 8 + ... + 2n.


Write the sum of the series 12 − 22 + 32 − 42 + 52 − 62 + ... + (2n − 1)2 − (2n)2.


3 + 7 + 14 + 24 + 37 + ...


1 + 3 + 6 + 10 + 15 + ...


1 + 4 + 13 + 40 + 121 + ...


2 + 4 + 7 + 11 + 16 + ...


If ∑ n = 210, then ∑ n2 =


If Sn = \[\sum^n_{r = 1} \frac{1 + 2 + 2^2 + . . . \text { Sum to r terms }}{2^r}\], then Sn is equal to


Write the sum of 20 terms of the series \[1 + \frac{1}{2}(1 + 2) + \frac{1}{3}(1 + 2 + 3) + . . . .\]


Write the 50th term of the series 2 + 3 + 6 + 11 + 18 + ...


Let Sn denote the sum of the cubes of first n natural numbers and sn denote the sum of first n natural numbers. Then, write the value of \[\sum^n_{r = 1} \frac{S_r}{s_r}\] .


The sum to n terms of the series \[\frac{1}{\sqrt{1} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{7}} + . . . . + . . . .\]  is


The sum of the series

\[\frac{1}{\log_2 4} + \frac{1}{\log_4 4} + \frac{1}{\log_8 4} + . . . . + \frac{1}{\log_2^n 4}\] is


If the sum of first n even natural numbers is equal to k times the sum of first n odd natural numbers, then write the value of k.


3 + 5 + 9 + 15 + 23 + ...

 

Find the sum of the series (33 – 23) + (53 – 43) + (73 – 63) + … to n terms


If |x| < 1, |y| < 1 and x ≠ y, then the sum to infinity of the following series:

(x + y) + (x2 + xy + y2) + (x3 + x2y + xy2 + y3) + .... is ______.


Let Sn(x) = `log_a  1/2 x + log_a  1/3 x + log_a  1/6 x + log_a  1/11 x  +  log_a  1/18 x + log_a  1/27x  + ` ...... up to n-terms, where a > 1. If S24(x) = 1093 and S12(2x) = 265, then value of a is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×