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Question
Show that the following statement pattern in contingency :
(~p v q) → [p ∧ (q v ~ q)]
Solution
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| p | q | ~q | ~q | ~p ∨ q | q ∨ ~q | p ∧ (q ∨ ~q) | (~p ∨ q) → [p ∧ (q ∧ ~ q)] |
| T | T | F | F | T | T | T | T |
| T | F | F | T | F | T | T | T |
| F | T | T | F | T | T | F | F |
| F | F | T | T | T | T | F | F |
From the entries in the last column, it follows that the given statement pattern is a contingency.
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