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Question
Using truth table verify that:
(p ∧ q)∨ ∼ q ≡ p∨ ∼ q
Solution
| p | q | ∼ q | p ∧ q | (p ∧ q) ∨ ∼ q | p ∨ ∼ q |
| T | T | F | T | T | T |
| T | F | T | F | T | T |
| F | T | F | F | F | F |
| F | F | T | F | T | T |
∴ (p ∧ q)∨ ∼ q ≡ p∨ ∼ q
Hence proved.
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