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Sum of All Two Digit Numbers Which When Divided by 4 Yield Unity as Remainder is - Mathematics

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Question

Sum of all two digit numbers which when divided by 4 yield unity as remainder is

Options

  • 1200

  •  1210

  • 1250

  • none of these.

MCQ

Solution

1210

The given series is 13, 17, 21....97.

\[a_1 = 13, a_2 = 17, a_n = 97\]

\[d = a_2 - a_1 = 7 - 3 = 4\]

\[a_n = 97\]

\[ \Rightarrow a + \left( n - 1 \right)d = 97\]

\[ \Rightarrow 13 + \left( n - 1 \right)4 = 97\]

\[ \Rightarrow n = 22\]

Sum of the above series:

\[S_{22} = \frac{22}{2}\left\{ 2 \times 13 + \left( 22 - 1 \right)4 \right\}\]

\[ = 11\left\{ 26 + 84 \right\}\]

\[ = 1210\]

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Chapter 19: Arithmetic Progression - Exercise 19.9 [Page 51]

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RD Sharma Mathematics [English] Class 11
Chapter 19 Arithmetic Progression
Exercise 19.9 | Q 4 | Page 51

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