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Question
The principal solution of the equation cot x=`-sqrt 3 ` is
Options
`pi/6`
`pi/3`
`(5pi)/6`
`(-5pi)/6`
Solution
`(5pi)/6`
`cot x =-sqrt 3`
`cotx= -cotx`
we know `cotx` is negative in 2nd and 4th quadrant so, we convert this 2nd or 4th
now
`cotx=-cotx=cot (pi-(5pi)/6)`
`x=(5pi)/6`
also
`cotx=cot (2pi-(11pi)/6)`
`x=(11pi)/6`
only option given is `(5pi)/6`
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